18x^2-6400x+275000=0

Solution for 18x^2-6400x+275000=0 equation:

18x^2-6400x+275000=0

a = 18; b = -6400; c = +275000;
Δ = b2-4ac
Δ = -64002-4·18·275000
Δ = 21160000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{21160000}=4600$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6400)-4600}{2*18}=\frac{1800}{36}
=50
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6400)+4600}{2*18}=\frac{11000}{36}
=305+5/9
$